if a:b3:4b:c=5:6and c:d=11:9 then a:d is
shadowsabers03:
Is that b^3 or b x 3?
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Given,
a:b = 3:4
=> a/b = 3/4 --------------------------->(1)
b:c = 5:6
=> b/c = 5/6 -------------------------->(2)
(1) × (2) => a/b × b/c = 3/4 × 5/6
=> a/c = 5/8 ------------------>(3)
Again,
c:d = 11:9
=> c/d = 11/9 ----------------------------------->(4)
(3) × (4) => a/c × c/d = 5/8×11/9
=> a/d = 55/72
Therefore, a:d = 55:72 .
a:b = 3:4
=> a/b = 3/4 --------------------------->(1)
b:c = 5:6
=> b/c = 5/6 -------------------------->(2)
(1) × (2) => a/b × b/c = 3/4 × 5/6
=> a/c = 5/8 ------------------>(3)
Again,
c:d = 11:9
=> c/d = 11/9 ----------------------------------->(4)
(3) × (4) => a/c × c/d = 5/8×11/9
=> a/d = 55/72
Therefore, a:d = 55:72 .
Answered by
1
a : b = 3 : 4 = 3 x 5 : 4 x 5 = 15 : 20
b : c = 5 : 6 = 5 x 4 : 6 x 4 = 20 : 24
( Multiplied for equalizing b in both, here it would have been 20.)
∴ a : b : c = 15 : 20 : 24
∴ a : c = 15 : 24 = 5 x 3 : 8 x 3 = 5 : 8
a : c = 5 : 8 = 5 x 11 : 8 x 11 = 55 : 88
c : d = 11 : 9 = 11 x 8 : 9 x 8 = 88 : 72
( Multiplied for equalizing c in both, here it would have been 88.)
∴ a : c : d = 55 : 88 : 72
∴ a : d = 55 : 72
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