If a bag contains Red , Blue and Green balls only then the sum of Probability of these elementary event is equal to 1.
P(R) + P(B) + P(G) = 1
Then,
P(not R) + P(not B) + P(not G) = ?
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11
Given,
P(R) + P(B) + P(G) = 1
Elementary event is equal to 1
So,
P(not R) + P(not B) + P(not G)=1
asraza812:
how? explain it
Answered by
3
P(R) + P(B) + P(G) = 1
Then,
P(not R) + P(not B) + P(not G) = 1
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