Question

If a ball dropped from a tower reaches the ground after 3.5 seconds, what is the height of the tower?

Given: g = –9.8 meters/second2

Answer 1

Answer:

To find the height of the tower, a formula for free-fall motion can be used, especially since the time and the force of gravity are given.

The formula is

h = (1/2)xg xt^2

Where:

h = height of the tower = ?

g = acceleration due to gravity = -9.8 m/s^2

t = time = 3.5 seconds

Substituting the given values:

h = (1/2)x(9.8)x (3.5)^2

h = 60.025 meters