If a ball hits the ground with velocity 'v', it bounces back up with velocity '-v'. If such a ball is dropped from a height 'h' above the ground , how high will it bounce? Justify you answer.
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there is no change in the magnitude of velocity after rebounding.
change in PE = change in KE of the ball when it hits the ground
mg h = 1/2 m v²
when the ball rebounds with velocity v, its initial KE = 1/2 m v²
when it reaches a height H, its PE = m g H.
SO using conservation of energy m g H = 1/2 m v²
hence H = h.
change in PE = change in KE of the ball when it hits the ground
mg h = 1/2 m v²
when the ball rebounds with velocity v, its initial KE = 1/2 m v²
when it reaches a height H, its PE = m g H.
SO using conservation of energy m g H = 1/2 m v²
hence H = h.
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