Physics, asked by prabhjotsingh7, 11 months ago

if a ball is made along the diameter of earth and an iron ball is dropped from one end of the bore, how the bar will behave in the bore?​

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Answered by maheshkumarpito
0

Answer:

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Correct option is

C

g

R

+4

g

2h

The ball is dropped from a point A at a height h above the surface. Thus during the entire motion, let the time taken by the ball to move move from A to B be t

1

, from B to C and C to B be t

2

, from C to D be t

3

, from D to C be t

4

, and from B to A be t

5

,

Let T be the time period of the complete motion.

Now for the motion A to B; h=0+

2

1

g(t

1

)

2

⟹t

1

=

g

2h

Similarly , t

3

=t

4

=t

5

=t

1

=

g

2h

As the time period of the particle executing SHM inside the tunnel is given by t=2π

g

R

e

Thus the time period of the motion of the ball inside the tunnel i.e B to C and C to B, t

2

=2π

g

R

Now the total time period of the motion T=t

1

+t

2

+t

3

+t

4

+t

5

⟹T=2π

g

R

+4

g

2h

solution

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