Question

if a ball is thrown horizontally from 200m high tower with velocity of 25m/s . find the time to reach the ground​

Answer 1

Answer:

time=distance/ speed

=200/25

=8

Answer 2

Answer:

2√5 sec

Explanation:

since the time is asked we will see the the y frame

In y frame the initial velocity is zero as the ball is thrown horizontally.

Therefore s=0.5× g×t^2

200=0.5×10×t^2

400÷10=t^2

hence t^2=40

t=2√5sec