Question

if a ball is thrown upward with a velocity 6m/s the maximum height attained by the particle is?​

Answer 1

Answer:

Explanation:

u =6m/s

v = 0 m/s

The value of acceleration due to gravity is g = 9.8 $m/s^{2}$

From equation, 2aS =$v^{2}$-$u^{2}$

S = $v^{2}$-$u^{2}$/ 2a

=> 0 – (6)2  /  2* 9.8

 = 0.61 m

please mark me brainliest

Answer 2

Answer:

refer to the below image

Explanation:

.