If a ball is thrown upward with
velocity ‘v', it attained a height of
100m. Find the height attained if
initial velocity of ball is 2v.
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Given : a ball is thrown upward with velocity ‘v', attained a height of 100m.
To Find : height attained if initial velocity of ball is 2v.
Solution:
Initial KE = (1/2)mv²
Initial PE = 0
At Highest point
KE = 0
PE = mgh
=> (1/2)mv² = mgh
=> v² = 2gh
=> v² = 2g(100)
=> v² = 200g
if v = 2v
then
mgh = (1/2)m(2v)²
=> h = 2v²/g
=> h = 2 * 200g /g
=> h = 400
height attained = 400 m
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