Question

If a ball is thrown vertically upward at the height of 80m then find the time to reach the highest point

Answer 1

Explanation:

Given:

H = 80m

By Using formula

$\boxed{\bold{\mathsf{H = \frac{u^{2}}{2g} }}}$

$\implies{\bold{\mathsf{ G\: is \:Taken \:as \: 10}}}$m/sec

$\implies$

$80 = \frac{ {u}^{2} }{2g} \\ \\ 80 \times 2 \times 10 = {u}^{2} \\ \\ {u}^{2} = 1600 \\ \\ u = \sqrt{1600} \\ \\ u = 40 \: m {sec}^{ - 1}$

Now by using formula for Time of Ascent = u/g

= 40/10

= 4 sec.

$\rule{200}{1}$

◽Time of Ascent: It is actually the time taken by body which is thrown up to reach the maximum height h is called as time of ascent.