Question

If a ball is thrown vertically upward with a velocity of 40m/s,then what will be the magnitude of its displacement agter 6s

Answer 1

V square minus 'u' square equal to 2gh
then h equals to 'u' square / 2g
h=1600/20
h=40 meters
$t = \sqrt{ \frac{2h}{g} }$
$t = 4s$
they asked the magnitude of displacement when the time is 6s
t(net)=2s
$t(net) = \sqrt{ \frac{2x}{g} } \: \: (let \: other \: height = x$
$4 = \frac{2x}{g}$
$x = 20meters$
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