Question

If a ball is thrown vertically upward with a velocity of 40m/s. Then what will be the magnitude of its displacement after 6s.

Answer 1

$u = 40 m \: per \: s \\ v = x \:m \: per \: s \\ a \: = - 10m {s}^{2} \: \\ v = u + at \\ x = 40 + ( - 10 \times 6) \\ x = 40 - 60 = - 20ms \\ \\ 2as = {v}^{2} - {u}^{2} \\ 2 \times ( - 10) \times s = ( { - 20)}^{2} - ( {40)}^{2} \\ - 20s = 400 - 1600 \\ - 20s = - 1200 \\ s = \frac{1200}{20} = 60m$