Question

If a ball is thrown vertically upwards with speed u, the distance covered during the last t seconds of its ascent is​

Answer 1

Answer:

Distance covered by a body projected vertically in the last one second in ascent = Distance covered by it in 1st second of decent or downward journey = g/2

Explanation:

We all know that for a body falling downwards, s =1/2gt2

substituting t=1 gives us s=g/2