Question

If a ball of 80 kg mass hits an ice curve and temperature of ball is 100°C, how much ice converts into water? Specific heat of ball is 0.2 cal/gram.​

Answer 1

Answer:

If m is the mass of ice melted, then heat spent in melting = heat supplied by the ball

m

L

=

s

M

Δ

T

m

×

80

=

0.2

×

(

80

×

1000

)

×

100

or

m

=

2

×

10

4

g