Question

if a ball of mass 5kg release from 5m above the ground what its velocity just before hitting the ground​

Answer 1

Answer:

10m/s^2

Explanation:

mgh = 1/2×mv^2

where m is the mass of the body=5m

v is velocity

g is acceleration due to gravity =10m/s^2  

h is the height =5m

5*10*5=1/2*5*v^2

v^2=250*2/5

v^2=100

v=√100

v=10m/s^2