Question

if a ball os dropped from a tower of height H it reaches the ground in 5 second .find the height of the tower

Answer 1

Explanation:

let g = 10m/s^2

u= 0

t=5s

we know that

h=ut+1/2at^2

=0×5+1/2×10×(5)^2

=5×25

=125m

Answer 2

Answer:

125 m

Explanation:

Since the body is falling freely ,

u = 0

a = g = 10 m/s²

t = 5 sec

H = S = h

To find the height now , we use the second equation of motion i.e S = ut+1/2at²

since u = 0 and a = g ,

S = 1/2 gt²  

By substituting the values ,

S = 1/2 × 10 × 25

  = 5 × 25

  = 125 m

Since H = S = h ,

The height of the tower is 125 m

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