Question

if a ball released from the top of the building what will be its speed after 5 seconds​

Answer 1

u=0m/s

t=5 sec.

a=9.8m/s^2

v=?

By using,v=u+at

v=0+9.8×5

v=49m/s

its velocity after 5 seconds will be 49 m/s

HOPE IT WILL HELP YOU. ........

PLEASE MARK AS BRAINLIEST