Question

If a ball rolls (u=0) along a plane of 0.5 m of length in 4 seconds. The upper end of which is raised 0.02 m above the lower end ,then the acceleration due to gravity has value of

Answer 1

Explanation:

Given If a ball rolls (u=0) along a plane of 0.5 m of length in 4 seconds. The upper end of which is raised 0.02 m above the lower end ,then the acceleration due to gravity has value of

• So on an inclined plane a ball rolls down in 4 secs. There will be a friction as the ball rolls down without slipping. So there is a frictional force.
• Now if we draw a diagram we can see that
•              Sin theta = perpendicular / hypotenuse  
•                             = 0.02 / 0.5  
•                            = 1/25
• Now a = g sin theta / 1 + k^2 / r^2 where k is a constant and r is radius of gyration.
•          So 2/5 mr^2 = mk^2
•          Or k^2 / r^2 = 2/5
•     Substituting in a we get
•           a = g x 1/25 / 1 + 2/5
•              = g/25 x 5/7
•      Or a = g/35 m/s^2
• Now we need to find the acceleration due to gravity,
•   So S = ut + ½ at^2
•              = 0 + ½ x g/35 x 16
•        0.5 = 8g / 35
•         Or 8g = 0.5 x 35
•         Or g = 0.5 x 35 / 8
•         Or g = 17.5 / 8
•        Or g = 2.18 m/s^2

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https://brainly.in/question/1934033