if a ball throw up vertically wih velocity 10m/s.than what will the velocity after 2sec
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v = u + at
(Where v-final velocity, u-initial velocity, a- accleration, t- time)
= 10 + (-10)×2
=-10 m/s
(-ve sign denotes that the veolcity is against the force applied i.e. gravity in this case and a=-10 because retardation will take place as the ball is thrown upwards.)
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