If a ball thrown verticall upward with a velocity of 20m/sec then calculate its total distance covered in 3 sec
Answers
In your question, the initial velocity is given as 20m/s, i.e., u=20m/s, the final velocity that the ball can achieve at the maximum height is 0m/s, hence, v=0m/s. Since the only first that cause the acceleration is gravity, a is taken as g where g is acceleration due to gravity, and had a value of 9.81m/s2. But for simplicity, we can take the value of a to be 10m/s2, so a=10m/s2. Now, we need to find, what's s and t.
Note: Since the ball is thrown upwards, which is against the force of gravity (gravity always acts downwards), we need take the value of a (in this case, g) as −10m/s2.
Using the first equation,
v=u+at
0=20−10t
10t=20
t=2
Using the third equation,
v2=u2+2as
02=202+2×(−10)×s
20s=400
s=20
Hence, the ball will travel for 2 seconds and complete a distance of 20 metres upwards.
V=U+AT
20=U+(-10*3)
20=U-30
U=50
S=UT+1/2AT^2
S =50*3+1/2(-10)*9
S=150-45
S=105