If a balll is throne vertically downwards from height of tower 100 meter . In how much time body will strike the ground . g= 10 m/s -2
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1
★★
Let the time after which the ball hits the ground is ‛t’.
Initial Velocity of ball (u) = 0m/s
Effective acceleration (a) = 10m/s^2
Height (h) = 100m
h = ut + 1/2×(a)(t)^2
100 = 0(t) + 1/2×(10)(t)^2
100 = 5t^2
5t^2 = 100
t^2 = 20
t = √20
t = 2√5
t = 4.47 sec
Hence, the ball strikes the ground after 4.47 sec it was released.
Answered by
1
Answer:
10 m/s
Explanation:
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