if a,band c are interior angles of a triangles abc, then show that sin(b+c÷2)=cos a÷2
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Hey folk..!!
Here's your answer..
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@Rêyaañ11
Here's your answer..
HOPE IT HELPS...!
@Rêyaañ11
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angle a + angle b + angle c = 180° ( sum of angles of a triangle )
b + c = 180° - a
L.H.S,
sin( b+c ÷2 ) = sin ( 180 - a ÷2 ) = sin ( 90° - a\2) = cos a\2 = R.H.S
Hope it helps!!
b + c = 180° - a
L.H.S,
sin( b+c ÷2 ) = sin ( 180 - a ÷2 ) = sin ( 90° - a\2) = cos a\2 = R.H.S
Hope it helps!!
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