Question

if A bar . B bar = A bar *B bar
then angle between a bar and b bar is
A)0
B)pi/4
C)pi/2
D)pi

Answer 1

Answer: The angle between A and B is 0.

Explanation:

Dot product of two vectors a and b is defined as a.b = |a| |b| cos (β) , where β is the angle between the two given vectors a and b.

The result of dot product is a scalar quantity. Hence, dot product is also termed as as scalar product.

ATQ,

A.B = |A| × |B|

|A| × |B| cosβ =  |A| × |B|

cosβ = 1

β = 0°

Therefore, the angle between A and B is 0.

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Answer 2

Answer: The angle between A and B is 0.

Option 'A' is correct.

Explanation:

Dot product of two vectors a and b is defined as $a.b =$  $|a||b|cos\beta$ where $\beta$is the angle between the two given vectors $a$ and $b$.

The result of dot product is a scalar quantity. Hence, dot product is also termed as as scalar product.

According to given question,

$A.B = |A| |B|$

$|A||B|cos\beta = |A||B|$

$cos\beta = 1$

$\beta = 0$

Therefore, the angle between $A$ and $B$ is $0$.

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