Question

if A bar=icap+jcap and Bbar=2icap+2jcap then find Abar+Bbar and the angle made of resultant vector with x axis and y axis?
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Answer 1

A.B=ABcosθ

or (2i^−2j^−k^).(i^+j^)=ABcosθ

or 2−2=ABcosθ or cosθ=0⇒θ=90o

ii) Resultant, R=A+B=(2i^−2j^−k^)+(i^+j^)=3i^−j^−k^

The projection of resultant on x -axis =R.i^=3

iii) Here, P+A=j^

⇒P=j^−A=j^−(2

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Answer 2

Answer:

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Explanation:

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