Question

If a, Bare zeroes of the polynomial p(x) = 3x2 - 2x -
6, then find

(ii) a2 + B2 ​

Answer 1

Step-by-step explanation:

p(x)=3x^2 - 2x - 6

a and B are zeros. 2/3 = a+B and -6/3=aB

(a+B)^2 = 4/9

a^2 +B^2 + 2aB = 4/9

a^2 +B^2 = 4/9 - 12/3 = 4/9 - 4

a^2 +B^2 = 4 - 36 / 9 = -32/ 9