If a be a root of the equation x?-X-1 = 0 then prove that other root is a cube -3a
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Answer:
Let ß is one root and 2ß is 2nd root
x
2
−px+q=0 so,
The sum of the roots=P
ß+2ß=P
ß=
3
P
---(1)
The product of the roots =q
2ß.ß=q
2ß
2
=q
put eqn (1)
2(
3
P
)
2
=q
2P
2
=
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