If A be the A.M. of two positive unequal quantities x and y and G be their G. M, then
fa) A<G
(b) A>G
(c) AZG
(d) ASG
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Concept-
Use the formula of AM = (x + y)/2 and GM = √x y.
Given-
A be the A.M. of two unequal quantities x and y and G be their G. M.
Find-
Choose the correct option-
(a) A < G
(b) A > G
(c) A ≥ G
(d) A ≤ G
Solution-
A is the A.M. of x and y.
According to the question,
(x + y)/2 = A → Equation (1)
G is the G.M. of x and y.
According to the question,
√ab = G → Equation (2)
Now, (a + b)² > 0
or, (a + b)² - 4ab > 0
or, (a + b)² > 4ab
or, (a + b)² / 4 > ab
or, (a + b) / 2 > √ab [ By squaring both sides.]
or, A > G
Therefore, correct option is (b) , i.e. , A > G.
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