Math, asked by kumarimeenakshi560, 8 hours ago

if a beta are the two zeros of the polynomial f y is equal y square-8y+a and a square+beta squar is equal to 40 find the value of a​

Answers

Answered by arshiasankhyan
15

Answer:

Hi mate

Step-by-step explanation:

REFER THE ATTACHMENT

HOPE IT HELPS..

(^-^)

Attachments:
Answered by cute71367
5

Given :-

α and β are zeroes of f(y) = y² - 8y + a

To Find :-

Value of a

Solution :-

We know that

Sum of zeroes = -b/a

By putting value

α + β = -(-8)/1

α + β = 8/1

α + β = 8

Now

αβ = c/a

αβ = a/1

αβ = a

Now

(α + β) = 40

α² + β² + 2αβ = 40

Taking 2 as common

(α + β)² + 2αβ = 40

(8)² + 2(a) = 40

(64) + 2a = 40

2a = 64 - 40

2a = 24

a = 24/2

a = 12

Similar questions