Question

If a bike is traveling with velocity 10m/s and its uniform acceleration is 4m/s^ then velocity acquired by the bike in 10 second is? ​

Answer 1

Answer:

50 m/s

Explanation:

Given:

Initial velocity (u) = 10 m/s

Acceleration (a) = 4 m/s²

Time (t) = 10 seconds

To find:

Final velocity (v)

Method to find:

v = u + at

⇒ v = 10 + (4*10)

⇒ v = 10 + 40

⇒ v = 50 m/s

Hence, the velocity acquired by the bus in 10 seconds is 50 m/s.

Answer 2

Given :

• Initial velocity, u = 10 m/s
• Acceleration, a = 4 m/s²
• Time taken, t = 10 seconds

To find :

• Final velocity, v

According to the question,

By using Newtons first equation of motion,

➞ v = u + at

Where,

• v = Final velocity
• u = Initial velocity
• a = Acceleration
• t = Time

➞ Substituting the values,

➞ v = 10 + 4 × 10

➞ v = 10 + 40

➞ v = 50

• So,the final velocity is 50 m/s.

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More formulas :

First equation of motion :

• v = u + at

Second equation of motion :

• s = ut + ½ at²

Third equation of motion :

• v² = u² + 2as