Question

If a bike is traveling with velocity 10m/s and its uniform acceleration is 4m/s^ then velocity acquired by the bike in 10 second is? ​

Answer 1

Required Answer:

Given:

• Initial velocity (u) = 10m/s
• Acceleration (a) = 4m/s²
• Time taken (t) = 10s

To calculate:

• The velocity acquired by the bike i.e its final velocity (v)

Calculation:

By using 1st equation of motion:

• ${\underline {\underline {\large {\sf { v = u +at} }}}}$

Where,

※v = final velocity

※ u = initial velocity

※ a = acceleration

※ t = time

$\sf { ⇢ v = u +at }$

$\sf { ⇢ v = 10 +(4 \times 10)}$

$\sf { ⇢ v = 10 + 40}$

$\sf { ⇢ v =50m/s}$

Therefore,velocity acquired by the bike is 50m/s.

▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬

_______________________________________

More information!

Equations of motion:

• v = u + at
• s = ut + ½at²
• v² – u² = 2as

Where,

★ v = final velocity = m/s

★ u = initial velocity = m/s

★ a = acceleration = m/s²

★ s = distance/displacement = m

★ t = time = sec

Remember that!

• When a body starts from rest, its initial velocity is 0.

• When a body comes to stop or applies breaks, its final velocity is 0.

▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬

_______________________________________

Answer 2

u = 10 m/s

a = 4 m/s²

t = 10 s

We know,

v = u + at

⇒v = 10 m/s + (4 m/s²)(10 s)

⇒v = 10 m/s + 40 m/s

⇒v = 50 m/s