Question

If a bike is travelling with 30 m/s and it's uniform acceleration is 4m/s² Then find velocity acquired by the bike in 6 sec is ​

Answer 1

Given :-

Initial velocity of the bike = 30 m/s

Acceleration of the bike = 4 m/s²

Time taken by the bike = 6 sec

To Find :-

The velocity acquired by the bike.

Analysis :-

Here we are given with the initial velocity, acceleration and time taken by the bike.

In order to find the final velocity, substitute the given values accordingly using the first equation of motion.

Solution :-

We know that,

• v = Final velocity
• t = Time
• u = Initial velocity
• a = Acceleration

Using the formula,

$\underline{\boxed{\sf First \ equation \ of \ motion=v=u+at}}$

Given that,

Initial velocity (v) = 30 m/s

Acceleration (a) = 4 m/s²

Time (t) = 6 sec

Substituting their values,

⇒ v = 30 + 4 × 6

⇒ v = 30 + 24

⇒ v = 54 m/s

Therefore, the velocity acquired by the bike is 54 m/s.

Answer 2

Answer:

Given :-

• Initial velocity = 30 m/s
• Acceleration = 4 m/s²
• Time taken = 6 sec

To Find :-

Final velocity

Formula to be applied

$\frak \red{V = U + AT}$

V = Final Velocity

U = Initial velocity

A = Acceleration

T = Time

Solution :-

$\rm\implies V =30 + (4)(6)$

$\rm \implies \: V = 30 + 24$

$\frak \pink{V = \: 54 \: {ms}^{ - 1}}$

Hence :-

Final velocity is 54 m/s