Question

If a bike is travelling with velocity 10m/s and its uniform
acceleration is 4m/s?. Then velocity acquired by the bike
in 10 seconds is​

Answer 1

V = 50m/s.

Explanation:

apply the the first equation of motion,

v = u+at

u=10m/s

a=4m/s2

t=10s

v = 10 + 4×10

10 + 40.

=50m/s.

Answer 2

Answer:

• Final velocity is 50 m/s.

Given:

• Initial velocity = 10 m/s
• Acceleration = 4 m/s²
• Time taken = 10 sec

Explanation:

$\rule{300}{1.5}$

Here, we are given that a bike is travelling with the initial velocity of 10 m/s accelerating uniformly with a constant rate of 4 m/s². We are asked to find the velocity acquired by the bike in 10 sec.

From first kinematic equation we know,

$\longrightarrow{\sf{v\ =\ u\ +\ at}}$

Here,

• v denotes final velocity
• u denotes initial velocity
• a denotes acceleration
• t denotes time taken

Solving,

$\longrightarrow{\sf{v\ =\ u\ +\ at}} \\ \\ \\ \longrightarrow{\sf{v\ =\ 10\ +\ 4 \times 10}} \\ \\ \\ \longrightarrow{\sf{v\ =\ 10\ +\ 40}} \\ \\ \\ \longrightarrow{\sf{v\ =\ 50\ m/s}}$

∴ The final velocity of the bike is 50 m/s.

$\rule{300}{1.5}$