Question

if a binary number ends with 2 zeroes show that its decimal expression is divisible by 2^2(2 to the power 2)?​

Answer 1

Step-by-step explanation:

let a number = ..dcba00 (two)

= d×2^5+c×2^4+b×2^3+a×2^2+ 0×2^1+0×2^0

= d×2^5+c×2^4+b×2^3+a×2^2+ 0+0

= .d×2^5+c×2^4+b×2^3+a×2^2

= (..d× 2^3+c×2^2+b×2^1+a)2^2

= a multiple of 2^2

so if a binary number ends with 2 zeroes its decimal expression is divisible by 2^2(2 to the power 2).