Math, asked by vishalkhanal2006, 8 hours ago

If a binary number ends with two zeroes show that its decimal expres-
sion is divisible by 22.​

Answers

Answered by gopalpvr
2

Step-by-step explanation:

let the number =..dbca00(two)

= ..d×2^5+c×2^4+b×2^3+a×2^2+0×2^1+0×2^0

= .d×2^5+c×2^4+b×2^3+a×2^2+0+0

=(.d×2^3+c×2^2+b×2^1+a)2^2

= is a multiple of 2^2

so .d×2^5+c×2^4+b×2^3+a×2^2+0×2^1+0×2^0is divisible 2^2

If a binary number ends with two zeroes its decimal expres-sion is divisible by 2^2.

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