If a binary number ends with two zeroes show that its decimal expres-
sion is divisible by 22.
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Step-by-step explanation:
let the number =..dbca00(two)
= ..d×2^5+c×2^4+b×2^3+a×2^2+0×2^1+0×2^0
= .d×2^5+c×2^4+b×2^3+a×2^2+0+0
=(.d×2^3+c×2^2+b×2^1+a)2^2
= is a multiple of 2^2
so .d×2^5+c×2^4+b×2^3+a×2^2+0×2^1+0×2^0is divisible 2^2
If a binary number ends with two zeroes its decimal expres-sion is divisible by 2^2.
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