Physics, asked by p402949, 3 months ago

if a bird flying in the sky looks vertically down and sees a fish in water how does the fish appear to the bird

(a) at its actual position
(b)farther away then it's actually distance
(c) closer than its actual distance
(d) can not beseen​

Answers

Answered by devesh277
3

Answer:

A fish is vertically below a flying bird moving vertically down toward water surface. The bird will appear to the fish to be. moving faster than its real speed and never than its real distance

Answered by elangoramrajxc
3

Answer:

ANSWER

If μ be the relative refractive index of the 2 materials,

then

Apparent Height

Real Height

=

μ

1

Thus, the apparent height of the bird will be more when viewed by the fish.

For refraction at plane surface

v

μ

2

=

ω

μ

1

Let x be the height of bird above water For light travelling from bird to fish

μ

1

=1;μ

2

ω=−x

v

μ

=−

x

1

v=−μx

∣v∣=μx>x

Speed of bird=x

Apparent speed of bird=∣v∣

=μx

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