Question

if a, bita are the roots of the equation x² - p(x+1) - C =0, then(a+1) (bita +1) =

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Answer 1

Answer:

Solution

If α,β are the roots of x2−p(x+1)+C=0⇒x2−px+C−p=0 then 

α+β=p and

α.β=C−p

Hence

(α+1)(β+1) 

=αβ+(α+β)+1

=C−p+(p)+1

=C+1.

hope it will help you sis

Good night sweet dreams meet you tomorrow ( ^ _ ^ )

Answer 2

Step-by-step explanation:

if a, bita are the roots of the equation x² - p(x+1) - C =0, then(a+1) (bita +1) =

fine hru?