Question

if a=bk b=ck then show that (a+b+c)(a-b+c)​

Answer 1

Answer:

IN the step

Step-by-step explanation:

Given that

a=bk

b=ck

To Show

(a+b+c)(a-b+c) -----(eq1)

Solve

Putting the value of a and b in eq1

(a+b+c)(a-b+c)

(bk+ck+c)(bk-ck+c)

bk(bk-ck+c)+ck(bk-ck+c)+c(bk-ck+c)

b^2k^2-bck^2+bkc+bck^2-c^2k^2+c^2k+cbk-c^2k+c^2

Answer 2

answer:

2bca

step by step explanation:

(a+b+c) (a-b+c)

2-2+abc

2ab -2bc +2ca

2bca

would be the answer