If a body body start from rest and attain a velocity of su kish in 5 second, 5 find the accleration.
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Answer:
Given that,
A body starts from rest and moves with an acceleration of 2 m/s²
here,
Initial velocity of the body = 0 m/s
[because it was initially at rest]
Acceleration of the body = 2 m/s²
To find,
distance covered by body in the 10th second of its motion
We know that distance travelled in nth seconds
= u + a/2(2n - 1)
let the distance covered in 10th seconds be S10
here,
n = 10 s
initial velocity(u) = 0 m/s
acceleration(a) = 2 m/s²
putting the values
S10 = 0 + 2/2(2(10) - 1)
= 20 - 1
S10 = 19
so,
Distance travelled in 10th seconds
= 19 meter
Hope it helps you!!
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