If a body covers one-third of its total distance with speed v1 and remaining distance with speed v2.Then what will be its average speed.
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LET THE TOTAL DISTANCE BE 3S
WKT AVERAGE VELOCITY =TOTALDISTANCE /TOTAL TIME
LET THE VELOCITY OF THE OBJECT WHILE IT IS COVERING ONE THIRD OF THE DISTANCE BE V1 SIMILARLY IN 2 THIRD BE V2
TOTAL TIME = T1+T2
T1=S/V1 T2=2S/V2
AVERAGE SPEED = 3S/S/V1+2S/V2 [3S WHOLE DIVIDED BY]
=3S/S[1/V1+2/V2]
=3[V1][V2]/[V2- 2V1]
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