Question

If a body has a velocity 50m/s and the uniform acceleration is 5metre per second square , find the time it takes to travel a distance of 240m.

Answer 1

initial velocity (u) =50m/s
acceleration (a) = 5m/s^
time (t) = ?
distance (s) = 240 m


we know,
s = ut + 1/2 at^
240m = 50m/s * t + 1/2 * 5 * t^
240m = 50m/s * t + 5/2 * t^
t = 240 *2/

Answer 2

Concept:

Velocity is defined as the directional speed of an object in motion that is the rate of change of the object's position with respect to time.

Given:

The initial velocity, $u=50m/s$.

Acceleration, $a=5m/s^2$ and distance, $s=240m$.

Find:

The initial velocity of the body, $u=50m/s$ .

Uniform acceleration, $a=5m/s^2$ .

The distance traveled, $s=240m$.

Using the equation of motion,

$s=ut+\frac{1}{2}at^2$

$240=50t+\frac{1}{2}(5)t^2$

$5t^2+100t-480=0\\t^2+20t-96=0$

$(t-4)(t+24)=0$

Since time can not be negative.

So, $t=4sec$.

Therefore, the time it takes to travel the distance is $4sec$ .

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