Question

if a body has a velocity of 50m/s and the uniform acceleration is 5m/s sq. find the time it takes to travel a distance of 240m

Answer 1

Velocity of body, u = 50 m/s

acceleration, a = 5 m/s^2

distance travelled, s = 240m

let the time taken = t

We know that, s = ut + 1/2 at^2

=> 240 = 50t + 1/2 × 5 × t^2

=> 240 = 50t + 2.5 t^2

=> 2.5 t^2 + 50t -240 = 0

=> t^2 + 20t - 96 = 0

=> t^2 + 24t - 4t - 96 = 0

=> t(t + 24) - 4(t + 24) = 0

=>(t-4)(t+24) = 0

=> t = 4 second
(as t can't be -24)

Time is 4 second.

Answer 2

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Velocity of body, u = 50 m/s

acceleration, a = 5 m/s^2

distance travelled, s = 240m

let the time taken = t

We know that, s = ut + 1/2 at^2

=> 240 = 50t + 1/2 × 5 × t^2

=> 240 = 50t + 2.5 t^2

=> 2.5 t^2 + 50t -240 = 0

=> t^2 + 20t - 96 = 0

=> t^2 + 24t - 4t - 96 = 0

=> t(t + 24) - 4(t + 24) = 0

=>(t-4)(t+24) = 0

=> t = 4 second

(as t can't be -24)

Time is 4 second.

HOPE SO IT WILL HELP.....