Question

If a body having an initial velocity of 10 m/s moves with a uniform acceleration of 10 m/s2 then the final velocity when it covers the distance of 3 m is

Answer 1

u=10m/s
a=10m/s^2
s=3m
v=???

USE:
${v}^{2} - {u}^{2} = 2as$
${v}^{2} - {10}^{2} = 2.10.3$
v^2 = 60+100
= 160.

Answer 2

Explanation:

As we know that from equations of modion v ^ 2 - u ^ 2 = 2as

u = 10m / s

a = 6m / (s ^ 2)

5 = 3m

v =?

v ^ 2 - u ^ 2 = 295

v ^ 2 - (10) ^ 2 = 2(10)(3)

v ^ 2 - 100 = 60

v ^ 2 = 100 + 60

v ^ 2 = 160

v = sqrt(160)

V = 12.64m / s