Question

if a body having an initial velocity of 10m/s moves with uniform acceleration of 10m/s2 then final velocity when it covers a distance of 3m is​

Answer 1

Answer:

v=4√10 m/s=12.65 m/s

Explanation:

u=10 m/s

a=10 m/s²

s=3 m

v=?

v²-u²=2as

let v² be x

x-u²=2as

x=u²+2as

x=10²+2×10×3

x=100+60

x=160

v²=160

v=√(160)

v=√(4²×10)

v=4√10 m/s

v=12.65 m/s