Question

if a body having initial velocity of 20m/s acceleration at 0.2m/s2 then its final velocity after half a minute is ____m/s​

Answer 1

✯ Final velocity= 26 m/s ✯

Explanation:

Given:

• Initial velocity (u) = 20 m/s
• Acceleration (a) = 0.2 m/s²
• Time (t) = ½ min = ½ × 60 = 30 s

To find:

• Final velocity.

Solution:

Let the final velocity be v m/s.

We know that,

$\sf{Acceleration (a)=\dfrac{Final\: velocity (v)-\: Initial\: velocity (u)}{Time (t)}}$

• [Put values]

$\implies\sf{0.2=\dfrac{v-20}{30}}$

$\implies\sf{v-20=0.2\times\:30}$

$\implies\sf{v-20=6}$

$\implies\sf{v=6+20}$

$\implies\sf{v=26}$

Therefore, the final velocity is 26 m/s.

_________________

★${\underline{\sf{\blue{Some\: formulas:-}}}}$

• v = u + at

• v² = u² + 2as

• s = ut + ½ at²

• $\sf{s_n=u+\dfrac{1}{2}a(2n-1)}$

Answer 2

Answer:

Explanation:

Given:

Initial velocity (u) = 20 m/s

Acceleration (a) = 0.2 m/s²

Time (t) = ½ min = ½ × 60 = 30 s

To find:

Final velocity.

Solution:

Let the final velocity be v m/s.

We know that,

\sf{Acceleration (a)=\dfrac{Final\: velocity (v)-\: Initial\: velocity (u)}{Time (t)}}Acceleration(a)=

Time(t)

Finalvelocity(v)−Initialvelocity(u)

[Put values]

\implies\sf{0.2=\dfrac{v-20}{30}}⟹0.2=

30

v−20

\implies\sf{v-20=0.2\times\:30}⟹v−20=0.2×30

\implies\sf{v-20=6}⟹v−20=6

\implies\sf{v=6+20}⟹v=6+20

\implies\sf{v=26}⟹v=26

Therefore, the final velocity is 26 m/s.

_________________

★{\underline{\sf{\blue{Some\: formulas:-}}}}

Someformulas:−

• v = u + at

• v² = u² + 2as

• s = ut + ½ at²

• \sf{s_n=u+\dfrac{1}{2}a(2n-1)}s

n

=u+

2

1

a(2n−1)

Explanation:

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