Question

if a body is dropped from___ meters height,it meets the ground after 3 sec ?
a) 25
b)100
c)19
d)44.1​

Answer 1

Explanation:

HEY MATE YOUR ANSWER IS HERE ^_^

GIVEN THAT

u = 0

t = 3

g = 9.8

S = ut + 1/2*gt^2

S = 0 + 1/2*9.8*9

S = 4.9*9

S = 44.1

HENCE ANSWER IS OPTION (d) 44.1

PLEASE MAKE ME A BRAINLIST ANSWER FOR THE QUESTION.

Answer 2

The height from which the ball is dropped is 45m.

Given:-

Time taken by the ball = 3sec

To Find:-

The height from which the ball is dropped.

Solution:-

We can easily find out the height from which the ball is dropped by using these simple steps.

As

Time taken by the ball (t) = 3sec

a = 10m/s²

and since the ball is being dropped, it will not have any initial velocity,

So, initial velocity (u) = 0

Height (h) =?

So, according to the second equation of motion

$h = ut + \frac{1}{2} a {t}^{2}$

on putting the values we get,

$h = 0 \times 3 + \frac{1}{2} \times 10 \times {3}^{2}$

$h = 0 + 5 \times 9$

$h = 5 \times 9$

$h = 45m$

Hence, The height from which the ball is dropped is 45m.

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