Question

If a body is just released from a height 80m above the ground. What time it will take to reach the ground

Answer 1

$s = ut + \frac{1}{2}g {t}^{2}$
u=0
because it was just released
therefore 'ut'=0
distance(s)=80

$80 = \frac{1}{2} \times 10 \times {t}^{2} \\ {t}^{2 } = 16 \\ t = 4secs$