Question

If a body is moving in circular path of radius 14 m.
It complete one revolution in 7 s. Considering the
speed to be uniform, the value of centripetal
acceleration is
[NCERT Pg. 80]
(1) x2 m/s2
(2) T2 m/s2
7
(3) --2 m/s2
(4) ? m/s2
8​

Answer 1

Answer:

8π²/7

Explanation:

• The body completes 1 revolution i.e 2π rad in 7 sec
• thus angular velocity ω= θ/t =2π/7 rad/s
• Therefore , centrepetal acceleration = ω²r = (2π/7)²×14 = 8π²/7

HOPE IT HELPS YOU!

Answer 2

Explanation:

centripetal acceleration= 8π²/7