Question

If a body is moving in circular path of radius 14m.It complete one revolution in 7s. Considering the speed to be uniform,the value of centripetal acceleration is​

Answer 1

Answer:

We know that Centripetal Force = v^2 / r

Calculate v

C_= 2pi R

2×3.14×14 = 87.92 or 88

Time taken to complete one revolution = 7

No. of revolution = 88/7

mujhe nhi aa rha

Answer 2

Answer :

a = 8π²/7 m/s²

Explanation :

Given,

• Radius of the circular path is 14 m

⇒ r = 14 m

• The body completes one revolution in 7s

⇒ T = 7 s

we know that,

Angular velocity is given by,

    $\sf \boxed{\omega =\frac{2 \pi}{T}}$

 ω = 2π/7 rad/s

Centripetal acceleration is given by,

  $\sf \boxed{\bf a = r \omega ^2}$

where

a - centripetal acceleration

r - radius of the circular path

ω - angular velocity

Substituting the values,

 a = 14 × (2π/7)²

 a = 14 × 4π²/49

 a = 8π²/7 m/s²

Therefore,

the centripetal acceleration is  $\bf \sf \frac{8}{7} \pi^2 \ m/s^2$