If a body is projected from a planet of gravity 20 m/s2 with radius of the planet as 10x10^6 km. what is the escape velocity of the body
Answers
Answered by
0
Answer:
27.9
√
5
k
m
−
s
−
1
Explanation:
hope it is helpful to you please mark me as brainlist
Answered by
0
Answer:
Using energy conservation principle
P.E.
i
+K.E
i
=P.E.
f
+K.E
f
where subscripts i and f for initial and final potential and kinetic energy of body
−
r
GMm
+
2
1
m(2v
e
)
2
=0+
2
1
mv
′
2
...(i)
v
e
=
2GM
R⇒
R
GM
=
2
v
e
2
...(ii)
substituting relation in equation (i)
−m
2
1
v
e
2
+
2
1
m(2v
e
)
2
=
2
1
mv
′
2
Solving for v
′
=
3
v
e
=19.4km/s
Similar questions