Question

if a body is projected with a velocity 10 root 2 metre per second make an angle 45° with the horizontal then the velocity of particle at maximum height is

Answer 1

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Answer 2

$ASSALAMUALAIKUM$

In the given case applying the formula to find maximum height reached by the projectile,we get,

 H=u²sin²θ / 2g

=1002 / 2×2x9.8

=2.54m

(where, u is the velocity of projection and θ is the angle of projection w.r.t horizontal)

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