Question

if a body is projected with a velocity 20√2 m/s making an angle 45° horizontal then initial velocity of particle in vector form is ​

Answer 1

Answer:

Explanation :

Component of velocity in x axis

= (20√2 cos 45)

=20√2 × 1/√2

=20 i^

{i^ is unit vector along x-axis}

Component of velocity in y axis

=20√2 sin45

=20√2 × 1/√2

= 20 j^.

{j is unit vector along y axis}

Initial velocity in vector form

= 20 i^ +20 j^